Вопрос по отладчику Unreal Speccy

[Shadow Maker]

Ну мне команду кто-нибудь скажет, которую вбить в отладчик? При чем тут непосредственная или косвенная запись мне решительно непонятно. Вот выдержка из хелпа.

       operators (in priority order):
         () ! ~ M(x) -> * % / + - >> << > < == = <= >= != & ^ | && ||
       operands:
         a,b,c,d,e,h,l,bc,de,hl                 - common registers
         a',b',c',d',e',h',l',bc',de',hl'       - alternative registers
         ix,iy,pc,sp,i,r                        - control registers
         FD     - pentagon port #FD (also know as #7FFD)
         OUT    - port used in 'OUT' command (or 0FFFFFFFF when no outs)
         IN     - port used in 'IN'  command (or 0FFFFFFFF when no ins)
         VAL    - read/written value to port (only meaningful when OUT != 0FFFFFFFF or IN != 0FFFFFFFF)
         numbers - hex, but must start with digit: DFFD - wrong, 0DFFD - right
         characters - must be enclosed in single quotes ('A','B',etc..)
       all calculations uses 32-bit unsigned interger arithmetic
       if you are not familiar with C, use brackets as much as possible, due to
       non-intuitive operator's precedence, e.g.
       out & 0FF == 0FE   treated as 'out & (0FF == 0FE)' <- always 0

       M(x) is peek byte at address x (same as x->0)
       '=' is an alias for '==' (for pascal programmers)

       samples:

           (out+1) | (in+1)       - in/out to any port
           (in & 8001) == 0       - read keyboard row from <B> to <SPACE>
           !(out & 1)             - any out to port #FE
           (out & 0FF)==0BB && (val==0F3 || val==0F4) - reset General Sound
           (out & 0FF)==0FD && (val&7)==3   - set 3rd memory page
           (FD & 7) == 3                    - the same
           M(pc)==0CB && pc->1 >= 10 && pc->1 <= 17
                - set break on executing instruction "rl <reg>"

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