SjASMPlus от z00m

[0xDEAD]

Не могу понять, как правильно работать с IFUSED?

DEVICE ZXSPECTRUM48

ORG 0x8000


main:
<code>
<code>
<code>
<code>
<code>
ret

include "address.asm" ; здесь объявлен модуль coords
include "out43.asm"
include "sto_rec.asm"
include "pause.asm"
include "windows.asm"

Главная программа.

module coords

ifused XxXxXxX

XxXxXxX <code>
<code>
<code>
<code>
ret

endif

Файл address.asm, в котором объявлен модуль coords.

module windows

CLS <code>
<code>
<code>
<code>
<code>
call coords.XxXxXxX
ret

Другой модуль, который ссылается на ссылку в модуле coords.

Pass 3 complete
Errors: 4, warnings: 0, compiled: 870 lines, work time: 0.015 seconds
The terminal process "C:\Program Files\PowerShell\7\pwsh.exe -Command sjasmplus --sld=test.sld --fullpath test.asm" terminated with exit code: 1.

Terminal will be reused by tasks, press any key to close it.

> Executing task: sjasmplus --sld=test.sld --fullpath test.asm <

SjASMPlus Z80 Cross-Assembler v1.18.2 (https://github.com/z00m128/sjasmplus)
Pass 1 complete (0 errors)
Pass 2 complete (0 errors)
windows.asm(91): error: Label not found: windows.coords.XxXxXxX

Результат...
Что неправильно?

upd
"Known bug: when code is using label inside module "moduleX", like call labelY, only usage of moduleX.labelY label is noted. Then if you define "labelY" outside of module and hide it inside IFUSED labelY block, the call from module will be unable to find the routine.

Workaround: you can use the global-label operator @: "call @labelY" to trigger usage of the global "labelY", or you can use the alternative IFUSED syntax "labelY: IFUSED" which does not only check condition, but also does define the label. Once the label is defined, the "call labelY" line inside module will find the global variant and mark it as "used" correctly."
Оно?

Вроде бы, оно...
Но новая беда - если написать
labelY: IFUSED
то не работают временные метки.

[Advertiser]

[krt17]

			module n1
			call @m1.used1
			endmodule
			module m1
			ifused used1
used1
			nop
			jr	1F
			nop
1
			ret
			endif
			endmodule

Так работает, а с новым синтаксисом да, косяк.